training [private]

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  • Yes I do, dominate beats recessive traits unless there are two recessive.

  • Okay so, let's do a very basic lesson with cats.


    The most basic thing you will learn are the black factors.


    There are three black factors: black, chocolate, and cinnamon and their dilutes (blue, lilac, and fawn, respectively)


    Black is the most dominate of the three it's genotype is 'B'


    Chocolate is recessive to black but dominate to cinnamon. Chocolate is expressed by 'b'


    A cinnamon is recessive to the other two. Cinnamon is expressed by 'b1'


    For reference, this is a black cat:


    Chocolate:


    and Cinnamon


    I want you to do these practice problems. Always assume pairings are male x female because gender is important (though it doesn't really apply for these)


    black x black


    cinnamon x chocolate


    black x chocolate


    cinnamon x black

  • [fancypost borderwidth=0]


    [justify]i'm having trouble distinguishing the b1 and placing in in the punnent square.


    [/justify][/fancypost]

  • So, for the second one:


    b1 b1
    b bb1 bb1


    b bb1 bb1


    What does this punnet square tell you?
    chocolate can be represented by bb1 or bb


    black can be represented by BB, Bb or Bb1


    cinnamon can be represented by b1b1


    Just remember that the 1's are subscripts

  • [fancypost borderwidth=0]


    [justify]black x black
    all kittens will be black with a BB genotype.


    cinnamon x chocolate
    all kittens will be chocolate with a bb1 genotype.


    black x chocolate
    all kittens will be black with a Bb genotype.


    cinnamon x black
    all kittens will be black with a Bb1 genotype.


    [/justify][/fancypost]

  • Good! Do you have any questions?


    Here are some more practice problems


    black x chocolate


    cinnamon x black


    cinnamon x cinnamon

  • [fancypost borderwidth=0]


    [justify]black x chocolate
    all kittens will be black.


    cinnamon x black
    all kittens will be black.


    cinnamon x cinnamon
    all kittens will be cinnamon.


    and no questions. ^^ although I find it a bit ironic that there was a punnett square on my math homework and that I had to explain what it was and how to do it to my classmates.


    [/justify][/fancypost]

  • Haha alright.


    So, because we are on a fictional site, we always assume the dominate trait carries the recessive.


    So, when doing


    black x cinnamon


    black, cinnamon.


    Does this rule make sense?

  • [fancypost borderwidth=0]


    [justify]Yes, because then it allows a different variety of coat colours, even if it is one extra one.


    [/justify][/fancypost]

  • [fancypost borderwidth=0]


    [justify][font=georgia][color=#c5e0dc]black x chocolate
    black, chocolate.


    cinnamon x black
    black, cinnamon.


    [/justify][/fancypost]

  • Good! Now, lets move onto dilutions.


    Okay so for dilutions:


    D
    will not change the cat's appearance in anyway


    d
    Will dilute the cat's coat into a paler color


    Black becomes blue
    Chocolate becomes lilac
    Cinnamon becomes fawn
    Brown tabby becomes blue tabby
    Chocolate tabby becomes blue tabby
    Cinnamon tabby becomes fawn tabby
    Red tabby becomes cream tabby


    Blue = BB dd
    Lilac = bb dd
    Fawn = b1b1 dd


    For reference:





    Keep in mind that a dilute x dilute will only result in dilute kittens. A solid x solid can get solid and diluted kittens. A solid x dilute will get both solid and dilute


    Practice:


    black x blue


    cinnamon x blue


    blue x lilac


    chocolate x blue

  • I have a question, how would the Punnett square be assembled with the multiple genotype code?

  • [fancypost borderwidth=0]


    [justify]Alright for the first one:


    black x blue:
    black, blue.


    Right?


    [/justify][/fancypost]

  • Alright, for the first one, I'm having difficulty with the one sub allele.