Okay so, do you understand why you got your punnetts wrong?
training [private]
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Yes I do, dominate beats recessive traits unless there are two recessive.
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Okay so, let's do a very basic lesson with cats.
The most basic thing you will learn are the black factors.
There are three black factors: black, chocolate, and cinnamon and their dilutes (blue, lilac, and fawn, respectively)
Black is the most dominate of the three it's genotype is 'B'
Chocolate is recessive to black but dominate to cinnamon. Chocolate is expressed by 'b'
A cinnamon is recessive to the other two. Cinnamon is expressed by 'b1'
For reference, this is a black cat:
Chocolate:
and Cinnamon
I want you to do these practice problems. Always assume pairings are male x female because gender is important (though it doesn't really apply for these)
black x black
cinnamon x chocolate
black x chocolate
cinnamon x black
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[fancypost borderwidth=0]
[justify]i'm having trouble distinguishing the b1 and placing in in the punnent square.
[/justify][/fancypost]
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So, for the second one:
b1 b1
b bb1 bb1b bb1 bb1
What does this punnet square tell you?
chocolate can be represented by bb1 or bbblack can be represented by BB, Bb or Bb1
cinnamon can be represented by b1b1
Just remember that the 1's are subscripts
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[fancypost borderwidth=0]
[justify]black x black
all kittens will be black with a BB genotype.cinnamon x chocolate
all kittens will be chocolate with a bb1 genotype.black x chocolate
all kittens will be black with a Bb genotype.cinnamon x black
all kittens will be black with a Bb1 genotype.[/justify][/fancypost]
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Good! Do you have any questions?
Here are some more practice problems
black x chocolate
cinnamon x black
cinnamon x cinnamon
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[fancypost borderwidth=0]
[justify]black x chocolate
all kittens will be black.cinnamon x black
all kittens will be black.cinnamon x cinnamon
all kittens will be cinnamon.and no questions. ^^ although I find it a bit ironic that there was a punnett square on my math homework and that I had to explain what it was and how to do it to my classmates.
[/justify][/fancypost]
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Haha alright.
So, because we are on a fictional site, we always assume the dominate trait carries the recessive.
So, when doing
black x cinnamon
black, cinnamon.
Does this rule make sense?
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[fancypost borderwidth=0]
[justify]Yes, because then it allows a different variety of coat colours, even if it is one extra one.
[/justify][/fancypost]
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Good, so pick like two or three of the practice problems we already did but apply this rule.
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[fancypost borderwidth=0]
[justify][font=georgia][color=#c5e0dc]black x chocolate
black, chocolate.cinnamon x black
black, cinnamon.[/justify][/fancypost]
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Good! Now, lets move onto dilutions.
Okay so for dilutions:
D
will not change the cat's appearance in anywayd
Will dilute the cat's coat into a paler colorBlack becomes blue
Chocolate becomes lilac
Cinnamon becomes fawn
Brown tabby becomes blue tabby
Chocolate tabby becomes blue tabby
Cinnamon tabby becomes fawn tabby
Red tabby becomes cream tabbyBlue = BB dd
Lilac = bb dd
Fawn = b1b1 ddFor reference:
[img width=510 height=347]http://fc06.deviantart.net/fs4…/Cat_Bus__by_Plodding.jpg[/img]
[img width=510 height=340]http://fc03.deviantart.net/fs7…garden_by_Sakiyo_chan.jpg[/img]
Keep in mind that a dilute x dilute will only result in dilute kittens. A solid x solid can get solid and diluted kittens. A solid x dilute will get both solid and dilute
Practice:
black x blue
cinnamon x blue
blue x lilac
chocolate x blue
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I have a question, how would the Punnett square be assembled with the multiple genotype code?
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Like this:
BB Dd
BB
dd
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I'm still rather confused, I apologize. Could you explain? ^^
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No, it's fine
Because, I can't make thing on MS paint, I found a good website. Read through this and tell me if you have any questions. Then do a black x fawn pairing.
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[fancypost borderwidth=0]
[justify]Alright for the first one:
black x blue:
black, blue.Right?
[/justify][/fancypost]
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Yeah! Okay, so try these
fawn x blue
chocolate x black
cinnamon x lilac
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Alright, for the first one, I'm having difficulty with the one sub allele.



