Fasthearts and Elliefangs math fight!

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    me and Elliefang are going to have a math fight. so then in a moneth or so, ill make a poll to see who is better. so here is my first math fight post:


    Here is my E=MC2 equation:


    if you have 4535.92 grams of brick (10 pounds)


    and divide that by 2159.961904761905cm3


    you come out with a dinsity of approximatly: 2.01 g. per cm3.


    i found that out by dividing 4535.92 g. by 2159.961904761905cm3 i got aproximatly 2.01 g. per cm3.


    so if you want to play around with different masses and stuff fell free to. so lets get on with E=mc2.


    Now just for your info, please look at the information below:


    E= energy


    m= mass


    c= speed of light


    2= Squared.


    and the mc2, it isn't m*c= then 2 it. its m*c2. that will be vital to know.


    now that you know that we can get on with the real buisnuss.


    since we know what the mass is, 10 pounds lets say. of bricks.


    so now we will need to convery that into kg.


    so that will = 10 lb. = 4535.92 g. /1000 = 4.53592.


    now that we know that we need to find out the speed of light.


    the speed of light = 300,000,000 mps (meters per second.)


    now if we 2 that we would get:


    300,000,000 x 300,000,000 = 90000000000000000


    now we are getting to the fun part!


    now just so you know, the form of energy im using is a joule.


    1 joule is equivlant to the energy gave off when you drop a text book to the floor. that isn't much, huh?


    so here is the E=MC2 part!


    we know now the following:


    m= mass= 4.53592


    c2= speed of light squared= 90000000000000000


    so if E= that multiplyed here is what we get:


    4.53592 x 90000000000000000 = E


    so now lets caulculate.............loaded


    so E = 408232800000000000 joules!


    WOW!! THATS A LOT!!


    are you wondering if thats right? 10 pounds of bricks.


    If you consider all the energy in the full kilogram of water, which also contains oxygen atoms, the total energy equivalent is close to 10 million gallons of gasoline!


    Can all this energy really be released?


    Has it ever been?


    The only way for ALL this energy to be released is for the kilogram of water to be totally annhilated.


    This process involves the complete destruction of matter, and occurs only when that matter meets an equal amount of antimatter.


    a substance composed of mass with a negative charge.


    Antimatter does exist;


    it is observable as single subatomic particles in radioactive decay,


    and has been created in the laboratory! WOW! AMAZING!


    But it is rather short-lived


    since it annihilates itself and an equal quantity of ordinary matter as soon as it encounters anything.


    For this reason, it has not yet been made in measurable quantities,


    so our kilogram of water can't be turned into energy by mixing it with 'antiwater'. At least, not yet.


    (maybe next year) lol!

    what is a b and c? are they elemants of mass or density abbreviations used for calclulating the quanton for the mass = d3=td2?

    This is how u do exponents on the computer:


    (a^3)(b^4) =ab^12 Idk if that's correct cuz i hate math's guts...but ya. I learned that this year. Calculus sux! Just thought i'd mention that...

    Fireheart, I'm not sure what that has to do with pure math. If you want to talk about physics, that's something else... but posting an example of E=mc^2 doesn't really count as an original idea. Here's an idea of my own, which IS original:


    What is a function representing the addition of all whole numbers between X and 0? For example, if X was 4, what would be 4+3+2+1+0? It would be 10, of course, but there should be a more efficient way to do this. I began by drawing a dot diagram of the example above.


    .
    . .
    . . .
    . . . .


    Hmm. This looks interesting. What would happen if we were to double it?


    . .
    . . . .
    . . . . . .
    . . . . . . . .


    Two triangle looking things! What would happen if we were to fit them into a rectangle?


    . . . . .
    . . . . .
    . . . . .
    . . . . .


    What do you know? The result of 2*(4+3+2+1) is equal to 4 squared plus 4. Let's see if it works with another example- (3+2+1).


    .
    . .
    . . .


    Double this, arrange it into a rectangle, and what do you get?


    . . . .
    . . . .
    . . . .


    In this example, you get 3^2 plus 3. I think you can begin to see the pattern here. Knowing this, you can arrange it into a function-


    y=(x^2+x)/2


    Where x is a number, and y is the sum of all whole numbers between x and 0.


    I then thought about using the same technique to reduce the factorial to a function, but quickly realized that this would be impossible. Can any of you tell me why this is?