Genetics 101. Private.

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  • [fancypost bordercolor=transparent; width: 350px][justify][size=8] Alright! So this is the thread where I will teaching you lot (:


    I have different weays of teaching, so some may leasrn faster than others. If you feel you need a private thread with me because this is to fast or slow, shoot me a pm and I can certainly do that!

    But while everyone migrates over here, I want you guys to tell me everything you know or think you know abut genetics (: It can even be that a black cat is blue! XD
    if you do that though... hererherher

  • Track ^^ Sorry I'm about to go to school.
    I've been reading through the little basic guide thing, Only started yesterday but I have a little idea of what to do.

  • [fancypost bgcolor= transparent; border: 0px black;margin-top: -10px;font-size:35px;font-family:georgia;color:white]AISHAH !
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    [fancypost bgcolor= transparent; border: 0px black;text-align:justify;font-size:14px;width:380px; color: white; text-transform: lowercase; font-family: arial;]hey! uhh..I don't really know much about genetics o.o or anything hehehe jk


    im dittoing riding crop when I say that I've looked over the guide :)




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    © COMET ✯
    #cometscodes

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    Well, I know the basics. That every gene has a dominate vs recessive probability that's sometimes calculated through the punnet square. That when both parents carry the same gene it results in homogeneous probability in the children, and that when both parents carry different genes it causes a heterogeneous probability of it going either way. Hmmm. Let's see. I am familiar with the concept of dominant carrying over recessive for the most part, but that the probability of two recessive genes carried from either parent is capable of being seen through the dominant gene. Or that two dominant genes can result in a mix of the genes. (I also studied plant genetics for a little bit, so I'm assuming it's the same as a red dominate gene crossing with a white dominant gene in roses to create pink.) Really, that's about it. I can probably brush up on my notes by reviewing the stuff I noted down from class, and investigate the other concepts via internet, but... yeah, I should probably read the basic guides provided in the genetics board. So I'll go do that now.


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  • [fancypost bordercolor=transparent; width: 350px][justify][size=8] All of yall are about on the same page, so ill just give yu a few definitions and few f the easier pairs once t try one youve read over.


    This wiill come from the black bases and dilutes.
    ((Once ive chceked yall off on this, ill post the official first lesson.


    ignore anything i say that involves reds for now.
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    Homozygous - when a cat has two copies of the same gene (e.g two black genes)
    Heterozygous - when a cat has two genes, each different. (e.g one chocolate and one black)
    Phenotype - the most basic way to describe something (e.g a cat, a dog)
    Genotype - the word used to reperesent a gene.
    Eumenalin - the word used to show the black gene.
    Pheomenalin - the word used to show the red gene.


    Before we start on the black gene, in my head I represent the black and red gene as a flower, the middle being the basic group (the black gene, the red gene) and the petals being sub catagories. (e.g black, chocolate, cinnamon)
    now, as mentioned above the eumenalin gene has 3 strands. black, cinnamon and chocolate.


    BB = Black
    bb = chocolate
    bb1 = cinnamon


    As you also may know, all cats on wcrpg carry dilute. The dilute for black is blue, the dilute for chocolate is lilac and the dilute for cinnamon is fawn.


    DD = non dilute
    Dd = non dilute cat carrying the dilute gene (but all cats carry this anyways)
    dd = dilute


    Try these. On the first two, try and guess the kittens and on the second two, try nd give me the genotypes, then ill get the first lesson up.


    1. Black xx Chocolate
    2. Fawn xx Cinnamon


    3. Blue
    4. Chocolate


    - dont worry about genders yet

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    Well, if I'm reading this right, then it'll go like this:
    1) Black X Chocolate
    BBDd X bbDd = BbDD, BbDd x2, Bbdd so the kittens have a chance of being black, chocolate or their dilutes, blue and lilac. That is, if both parents are Non-Dilute carrying dilute (since you said all cats carry dilute).
    2) Fawn X Cinnamon
    bb1dd X bb1Dd = bbDd, bb1Dd x2, bbdd, bb1dd x2 and I wasn't sure how to break up the b + b1 so I ended up with a b1b1dd twice. I figure the kittens have an equally small chance of coming out chocolate or lilac, a 25-75 of the kittens coming out cinnamon-fawn, and I dunno about the b1b1 genotype? I probably set up my square very wrong. Lalz.


    3) I'm pretty sure the genotype for Blue is BBdd.
    4) Also pretty sure the genotype for Chocolate is bbDD, or bbDd.


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  • [fancypost bgcolor= transparent; border: 0px black;margin-top: -10px;font-size:35px;font-family:georgia;color:white]AISHAH !
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    [fancypost bgcolor= transparent; border: 0px black;text-align:justify;font-size:14px;width:380px; color: white; text-transform:; font-family: arial;]hm, let's see..


    1. Bb, bb, BB, Bb
    2. uh...bb, bb, bb, bb?
    3. bb
    4. bb


    I doubt they're right x)


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    #cometscodes

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    assume all cat to carry there recessive oartners genes. this is done for variety so we dont have to get so technical about things xD pokes arz


    and Aishah, you're somewhat on the right track.
    Are there any questions before i post the lesson up?
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    Lol~ just with the fawnXchocolate. How do you figure out that one? Cause i know one eighth of the litter would have a 50-50 of chocolate-lilac, one eighth would come out lilic, one fourth would come out fawn and one fourth has a fifty-fifty of cinnamon or fawn. But then about that last genotype (b1b1Dd, b1b1dd)... what would that even come out as? o.O? Or am I just not splitting the parent genotypes correctly? The 1 is throwing me off completely.


    I'm pretty sure I got the Black x Chocolate though. >.> That one was fairly easy cause there wasn't any sneaky 1's in there to throw me off.


    And I am sorry, I do like to get down to the technicalities. It's just easier for me to absorb it when it's the baseline.


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    The post was edited 1 time, last by Arz ().

  • [fancypost bordercolor=transparent; width: 350px][justify][size=8] b1b1 is the cinnamon gene. In the lesson I'll have up soon, youll understand.


    Cinnamon is the most recessive of the black bases. Black and Chocolate are dominant over it. With that being said, Cinnamon needs two copies just to show up.


    As for the whole one-fourth fraction thing, we don't do that. It makes it very confusing and hard for everyone

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    Nah, that's just for me. I like keeping track of the probabilities. I'll remember not to use them on here though. ^^


    And okie. b1b1 is cinnamon? Then what's the bb1 you used in the initial post? Carrying the gene?


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    Okay! That's what was throwing me off. So then the genotype for cinnamon would be b1b1Dd and the genotype for fawn would be b1b1dd? so then Cinnamon x Fawn would be mostly fawn with some cinnamon thrown in there?


    I was using the bb1 for the cinnamon (because that's what you used on the post and I didn't really know better, lalz) but it makes much more sense now.


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    Hey guys! Machi says sorry for being absent and she'll be back later tonight!


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    Yay~ My studying finally gets to take a shot at practice!


    Black x Chocolate {Bb x bb} = Bb, bb
    Will have black and chocolate kittens.


    Cinnamon x Cinnamon {b1b1 x b1b1} = b1b1
    Will have cinnamon kittens.


    Chocolate x Cinnamon {bb1 x b1b1} = bb1, b1b1
    Will have chocolate and cinnamon kittens.


    Black (carrying cinnamon) x Chocolate (carrying cinnamon) {Bb1 x bb1} = Bb, bb1, Bb1, b1b1
    Will have Black kittens carrying chocolate, black kittens carrying cinnamon, chocolate kittens carrying cinnamon, and cinnamon kittens.


    Dilute~
    Fawn x Lilac {b1b1dd x bb1dd} = bb1dd, b1b1dd
    Will have lilac kittens carrying fawn, and fawn kittens.


    Blue x Blue {BBdd x BBdd} = BBdd
    Will have blue kittens.


    Blue x Fawn {Bb1dd x b1b1dd} = Bb1dd, b1b1dd
    Will have blue kittens carrying fawn, and fawn kittens.


    Black x Chocolate {BbDd x bbDd} = BbDD, BbDd, Bbdd, bbDD, bbDd, bbdd
    Will have black kittens carrying chocolate, black kittens carrying chocolate, blue and lilac, blue kittens carrying lilac, pure chocolate kittens, chocolate kittens carrying lilac, and pure lilac kittens.


    Cinnamon x Blue {b1b1Dd x Bb1dd} = Bb1Dd, Bb1dd, b1b1Dd, b1b1dd
    Will have black kittens carrying blue, cinnamon and fawn, blue kittens carrying fawn, cinnamon kittens carrying fawn, and pure fawn kittens.


    Black x Black {BBDd x BBDd} = BBDD, BBDd, BBdd
    Will have pure black kittens, black kittens carrying blue, and pure blue kittens.


    Question: On the genetics pairing board (yes I took a look again), there's "brown". How does brown differ from chocolate/cinnamon?


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  • [fancypost bgcolor= transparent; border: 0px black;margin-top: -10px;font-size:35px;font-family:georgia;color:white]AISHAH !
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    [fancypost bgcolor= transparent; border: 0px black;text-align:justify;font-size:14px;width:380px; color: white; text-transform: auto; font-family: arial;]hm..I'm a bit confused on the dilute but this is what I have:
    ( I'm assuming they have four kittens )


    Black xx Chocolate
    1. Bb
    2. Bb
    3. bb
    4. bb


    Cinnamon xx Cinnamon
    1. b1b1
    2. b1b1
    3. b1b1
    4. b1b1


    Chocolate xx Cinnamon
    1. bb1
    2. bb1
    3. b1b1
    4. b1b1


    Black (carrying cinnamon) xx Chocolate (carrying cinnamon)
    1. Bb
    2. Bb1
    3. Bb1
    4. b1b1


    --


    Fawn x Lilac.
    1. bb1dd
    2. bb1dd
    3. b1b1dd
    4. b1b1dd


    Blue x Blue.
    1. BBdd
    2. BBdd
    3. BBdd
    4. BBdd


    Blue x Fawn.
    1. Bb1dd
    2. Bb1dd
    3. b1b1dd
    4. b1b1dd


    Black xx Chocolate
    1. BbDd
    2. BbDd
    3. bbdd
    4. bbdd


    Cinnamon xx Blue
    1. Bb1Dd
    2. Bb1dd
    3. b1b1Dd
    4. b1b1dd


    Black xx Black
    1. BBDD
    2. BBdd
    3. BBdd
    4. BBDd


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    The post was edited 1 time, last by ⋆ aishah ⋆ ().

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    Aishah, I can try to explain how I understand the carrying and the dilute to work (and Machi correct me if I'm wrong).


    For the black carrying cinnamon x chocolate carrying cinnamon, think of it this way: Black and chocolate are dominate, correct? Cinnamon is recessive. So with the genotypes, you will have the dominate gene (aka Black, and Chocolate) followed by the recessive gene. So black carrying cinnamon will look like this: Bb1, or B for black and b1 for the recessive gene the cat carries. The same thing with chocolate. You'll have bb1, or b for chocolate and b1 for the recessive cinnamon. Then you just do a punnet square of Bb1 x bb1.


    Dilute is fairly simple if you think about it. Okay, so you're basic colors are: Black, blue, chocolate, lilac, cinnamon and fawn. Those are the ones we're working with right now. So now, mentally break them up into dense and dilute colors. Black, chocolate and cinnamon are the dense colors, but here on WCRPG, we assume they also carry dilute. So on their genotypes, add a capital D for dense and a lowercase d for dilute. Black, chocolate and cinnamon genotypes will then look like this in their base forms respectively: BBDd, bbDd, and b1b1Dd.


    Now with the dilutes, they have to be exclusively dilute, meaning there cannot be a dense gene (or capital D), so just make both D's lowercase. Blue, lilac and fawn genotypes look like this: BBdd, bbdd, and b1b1dd.


    Basically, when you set them up in a punnet square, you'll take one of the color genes and one of the dense/dilute genes for each combination.


    For example, with cinnamon x black (I use this one cause it's more difficult), the genotypes will be b1b1Dd and Bb1Dd. The top will break up as b1D and b1d, and the side will break up as BD, bd, b1D and b1d. Obviously, now your punnet square is getting bigger, and so are your yielding options. You can take a look at my practice (right above you) if you think you need it to check. Or ask me any questions. I am fairly confident with this stage of our learning thus far and I think I can answer anything about the dilute/dense if you need.


    I really suggest making a list of the genotypes for the basic colors, just a base board reference for what a genotype of Black, Blue, Chocolate, Lilac, Cinnamon and Fawn will look like in their purest forms. It helps to prevent confusion on a basic level.


    And remember! The dilute versions of the colors will be recessive to their dense partners as well as whatever the dense partner is recessive to (ie. Lilac is recessive to chocolate but also recessive to blue and black, yet dominate to cinnamon and fawn.)


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  • [fancypost bgcolor= transparent; border: 0px black;margin-top: -10px;font-size:35px;font-family:georgia;color:white]AISHAH !
    FIERCE[/fancypost]

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    [fancypost bgcolor= transparent; border: 0px black;text-align:justify;font-size:14px;width:380px; color: white; text-transform: lowercase; font-family: arial;]okay, wow, thanks for the help!
    Just to make sure: you said that here we assume that all genetopyes carry a dilute/recessive gene— so does that mean we'll never have a DD (or BB) for these lessons?




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    © COMET ✯
    #cometscodes

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    No, that is what I said but we're talking about the pure dominate forms. Example. If we're pairing Black with Lilac, if we had Black's genotype as BBDD then we would only ever see Black or Blue in the kittens because it is total dominate. So to give our kittens more variation, we have the dominates carry their recessive partners genes. So with lilac as Black's partner, we'd change Black's BBDD to BbDd. B for Black, b for chocolate, D for black's density, and d for lilac's dilute. Does that explanation clear up your confusion? Because I can go a little more into detail if need be. :)


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